JEE Main & Advanced Mathematics Straight Line Question Bank Self Evaluation Test - Straight Lines & Pair Striaght Lines

  • question_answer
    For \[a>b>c>0,\] the distance between (1, 1) and the point of intersection of the lines \[ax+by+c=0\] and \[bx+ay+c=0\] is less than \[2\sqrt{2}.\] Then

    A) \[a+b-c>0\]

    B) \[a-b+c<0\]

    C) \[a-b+c>0\]

    D) \[a+b-c<0\]

    Correct Answer: A

    Solution :

    [a] The intersection point of two lines is \[\left( \frac{-c}{a+b},\frac{-c}{a+b} \right)\] Distance between (1, 1) and \[\left( \frac{-c}{a+b},\frac{-c}{a+b} \right)<2\sqrt{2}\] \[\Rightarrow 2{{\left( 1+\frac{c}{a+b} \right)}^{2}}<8\] \[\Rightarrow 1+\frac{c}{a+b}<2\Rightarrow a+b-c>0\]


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