A) 12
B) 14
C) 16
D) 18
Correct Answer: A
Solution :
[a] \[{{X}^{3-}}\] has 14 protons, i.e., X also has 14 protons and therefore 14 electrons. \[X=14=1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{2}}\] \[{{X}^{2+}}=1{{s}^{2}},2{{s}^{1}}2{{p}^{6}},3{{s}^{2}}=12\]electronsYou need to login to perform this action.
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