A) 4 : 3
B) 1 : 2
C) 2 : 1
D) 3 : 4
Correct Answer: B
Solution :
[b] \[\frac{{{(KE)}_{1}}}{{{(KE)}_{2}}}=\frac{{{v}_{1}}-{{v}_{0}}}{{{v}_{2}}-{{v}_{0}}}\] \[=\frac{(1.5\times {{10}^{15}}-1\times {{10}^{15}})}{\left( 2.0\times {{10}^{15}}-1\times {{10}^{15}} \right)~}=\frac{1}{2}\]You need to login to perform this action.
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