A) 3
B) \[2\sqrt{2}\]
C) 1
D) 2
Correct Answer: B
Solution :
[b] \[{{\lambda }_{p}}=\frac{h}{\sqrt{2eV{{m}_{p}}}};\] \[{{\lambda }_{H{{e}^{2+}}}}=\frac{h}{\sqrt{2\times 2eV{{m}_{H{{e}^{2+}}}}}}=\frac{h}{\sqrt{2\times 2eV\times 4{{m}_{p}}}}\] \[\therefore \frac{{{\lambda }_{p}}}{{{\lambda }_{H{{e}^{2+}}}}}=2\sqrt{2}\]You need to login to perform this action.
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