A) \[6\times {{10}^{7}}\]
B) 10
C) 60
D) None of these
Correct Answer: C
Solution :
[c] No. of sodium lauryl sulphate molecules \[(C{{H}_{3}}{{(C{{H}_{2}})}_{11}}SO_{4}^{-}N{{a}^{+}})\] in 1 litre solution \[={{10}^{-3}}\times 6\times {{10}^{23}}=6\times {{10}^{20}}\] No. of sodium lauryle sulphate molecules per \[m{{m}^{3}}=6\times {{10}^{14}}\] No. of colloidal particles per \[m{{m}^{3}}={{10}^{13}}\] No. of molecules per colloidal particle \[=\frac{6\times {{10}^{14}}}{{{10}^{13}}}=60\]You need to login to perform this action.
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