A) 930
B) 520
C) 560
D) None of these
Correct Answer: C
Solution :
[c] \[\frac{Coagulation\,power\,of\,AlC{{l}_{3}}}{Coagulation\text{ }power\text{ }of\text{ }NaCl}\] \[=\frac{\text{ }Coagulation\text{ }value\text{ }of\,NaCl}{Coagulation\,value\,ofAlC{{l}_{3}}}\] \[=\frac{52}{0.093}=559.13\approx 560\]You need to login to perform this action.
You will be redirected in
3 sec