A) \[\Delta S\] is negative and, therefore, \[\Delta H\] should behighly positive
B) \[\Delta S\] is negative and therefore, \[\Delta H\] should be highly negative
C) \[\Delta S\] is positive and, therefore, \[\Delta H\] should be negative
D) \[\Delta S\] is positive and therefore, \[\Delta H\] should also be highly positive
Correct Answer: B
Solution :
[b] For adsorption \[\Delta S<0\] and for a spontaneous change \[\Delta G=-ve\] hence \[\Delta H\] should be highly negative which is clear from the equation \[\Delta G=\Delta H-T\Delta S\] \[=-\Delta H-T\left( -\Delta S \right)=-\Delta H+T\Delta S\] So if \[\Delta H\] is highly negative \[\Delta G\] will also be (-ve)
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