A) between 0 and 1 in all cases
B) between 2 and 4 in all cases
C) 1 in case of physical adsorption
D) 1 in case of chemisorption
Correct Answer: A
Solution :
[a] According to Freundlich adsorption isotherm \[\frac{x}{m}=k{{p}^{\frac{1}{n}}}\] at low pressure, \[\frac{1}{n}=1\] \[\therefore \frac{x}{m}\propto {{p}^{1}}\] at high pressure, \[\frac{1}{n}=0\] \[\frac{x}{m}\propto {{p}^{{}^\circ }}\] i.e., the value of n varies between 0 to 1
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