JEE Main & Advanced Physics Rotational Motion Question Bank Self Evaluation Test - System of Particles Rotational Motion

  • question_answer
    The mass per unit length of a non-uniform rod of length L varies as \[m=\lambda x\] where \[\lambda \] is constant. The centre of mass of the rod will be at:

    A) \[\frac{2}{3}L\]

    B) \[\frac{3}{2}L\]

    C) \[\frac{1}{2}L\]

    D) \[\frac{4}{3}L\]

    Correct Answer: A

    Solution :

    [a]\[{{X}_{cm}}=\int_{0}^{L}{\frac{(dm)x}{\int_{0}^{L}{(dm)}}=\frac{\int_{0}^{L}{(\lambda xdx)x}}{\int_{0}^{L}{(\lambda xdx)}}}=\frac{2L}{3}~~\]


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