A) 8.1 m/s
B) 7.3 m/s
C) 6.4 m/s
D) 5.3 m/s
Correct Answer: B
Solution :
[b] \[{{\overset{\to }{\mathop{v}}\,}_{cm}}=\frac{{{m}_{1}}\overset{\to }{\mathop{{{v}_{1}}}}\,+{{m}_{2}}\overset{\to }{\mathop{{{v}_{2}}}}\,}{{{m}_{1}}+{{m}_{2}}}=\frac{2\times 2+4\times 10}{2+4}=7.3m/s\]
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