A) \[\frac{L}{2}\]
B) L
C) \[\frac{L}{3}\]
D) \[\frac{L}{4}\]
Correct Answer: A
Solution :
[a] Angular momentum of particle is given by: \[L=m{{r}^{2}}\omega =2\pi m{{r}^{2}}f\] \[[\because W=2\pi f]\] If frequency is halved then, \[L'=m{{r}^{2}}\frac{\omega }{2}=\pi m{{r}^{2}}f\,\,\,\,\,\,\,\,\,\therefore L'=\frac{L}{2}\]
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