JEE Main & Advanced Physics Rotational Motion Question Bank Self Evaluation Test - System of Particles Rotational Motion

  • question_answer
    If the angular momentum of a particle of mass m rotating along a circular path of radius r with uniform speed is L, the centripetal force acting on the particle is

    A) \[\frac{{{L}^{2}}}{m{{r}^{2}}}\]

    B) \[\frac{{{L}^{2}}}{mr}\]

    C) \[\frac{L}{mr}\]

    D) \[\frac{{{L}^{2}}m}{r}\]

    Correct Answer: A

    Solution :

    [a] From the relation, angular momentum, \[L=mvr\]             \[v=\frac{L}{mr}\] Centripetal force acting on the particle \[F=\frac{m{{v}^{2}}}{r}=\frac{m{{\left( \frac{L}{mr} \right)}^{2}}}{r}=\frac{{{L}^{2}}}{m{{r}^{3}}}\]


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