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JEE Main & Advanced Physics Rotational Motion Question Bank Self Evaluation Test - System of Particles Rotational Motion

  • question_answer
    With 0 as the origin of the coordinate axis, the X and Y-coordinates of the centre of mass of the system of particles shown in the figure may be given as. Here m and 2m represent the masses of the particles.

    A) \[\left( -\frac{b}{2},0 \right)\]

    B) \[\left( -\frac{b}{2},b \right)\]

    C) \[\left( -\frac{b}{3},b \right)\]

    D) \[\left( -\frac{b}{2}b,b \right)\]

    Correct Answer: C

    Solution :

    [c] \[\overset{-}{\mathop{x}}\,=\frac{m(-2b)+2m(-b)+m\times 0+2m(b)}{m+2m+m+2m}=\frac{-b}{3}\] and\[\overline{y}=+b\]


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