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JEE Main & Advanced Physics Rotational Motion Question Bank Self Evaluation Test - System of Particles Rotational Motion

  • question_answer
    Two particles, each of mass 2 kg are put at (2m, 0) and (0, 2m), as shown in figure. Now 1 kg mass of particle A is put on to the particle B. The change in x-coordinate of centre of mass of the system is                    

    A) 0.5m

    B) 1m                

    C) 1.5m

    D) None of these     

    Correct Answer: A

    Solution :

    [a] \[\begin{align}   & {{x}_{i}}=\frac{2\times 2+2\times 0}{2+2}=1m.\,\,and\,\,{{x}_{f}}=\frac{1\times 2+3\times 0}{1+3} \\  & =0.5m. \\ \end{align}\] \[\therefore \,\,\Delta x=0.5m\]


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