JEE Main & Advanced Physics Rotational Motion Question Bank Self Evaluation Test - System of Particles Rotational Motion

  • question_answer
    The moment of inertia of a uniform circular disc of radius 'R' and mass 'M' about an axis passing from the edge of the disc and normal to the disc is

    A) \[M{{R}^{2}}\]

    B) \[\frac{1}{2}M{{R}^{2}}\]

    C) \[\frac{3}{2}M{{R}^{2}}\]

    D) \[\frac{3}{2}M{{R}^{2}}\]

    Correct Answer: C

    Solution :

    [c] M.I. of a uniform circular disc of radius 'R' and     mass 'M' about an axis passing through C.M and normal to the disc is \[{{I}_{C.M.}}=\frac{1}{2}M{{R}^{2}}\] From parallel axis theorem \[{{I}_{T}}={{I}_{C.M.}}+M{{R}^{2}}=\frac{1}{2}M{{R}^{2}}+M{{R}^{2}}=\frac{3}{2}M{{R}^{2}}\]


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