A) \[\frac{\pi }{18}Nm\]
B) \[\frac{2\pi }{15}Nm\]
C) \[\frac{\pi }{12}Nm\]
D) \[\frac{\pi }{15}Nm\]
Correct Answer: D
Solution :
[d] \[\tau \times \Delta t={{L}_{0}}\] \[\{\because \,\,\,\sin ce\,{{L}_{f}}=0\}\] \[or\,\,\,\,\,\,\tau \times 30=2\pi \] \[\tau =\frac{\pi }{15}N-m\]
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