A) \[M{{R}^{2}}/2\]
B) \[M{{R}^{2}}\]
C) \[2M{{R}^{2}}\]
D) \[M{{R}^{2}}/4\]
Correct Answer: A
Solution :
[a] Perp axis theorem \[{{I}_{x}}+{{I}_{y}}={{I}_{z}}\] \[\Rightarrow \,\,\,2I=M{{R}^{2}}\] So \[I=\frac{M{{R}^{2}}}{2}\]
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