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JEE Main & Advanced Physics Rotational Motion Question Bank Self Evaluation Test - System of Particles Rotational Motion

  • question_answer
    Linear acceleration of hallow cylinder of mass \[{{m}_{2}}\]is \[{{a}_{2}}\]Then angular acceleration\[{{\alpha }_{2}}\] is (given that there is no slipping).           

    A) \[\frac{{{a}_{2}}}{R}\]

    B) \[\frac{({{a}_{2}}+g)}{R}\]

    C) \[\frac{2({{a}_{2}}+g)}{R}\]

    D) None of these

    Correct Answer: C

    Solution :

    [c] \[{{m}_{2}}g-T={{m}_{2}}{{a}_{2}}\]     ? (i) \[TR=\frac{{{m}_{2}}{{R}^{2}}}{2}{{\alpha }_{2}}\]             ? (ii) \[{{\alpha }_{1}}R={{a}_{2}}-{{\alpha }_{2}}R\]           ? (iii) \[TR=\left( \frac{{{m}_{1}}{{R}^{2}}}{2} \right){{\alpha }_{1}}\]          ? (iv) \[{{\alpha }_{2}}=\frac{2T}{{{m}_{2}}R}=\frac{2}{{{m}_{2}}R}.({{m}_{2}}{{a}_{2}}+{{m}_{2}}g)\] \[=2\left( \frac{{{a}_{2}}+g)}{R} \right)\]


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