A) 1.12Nm
B) 0.83Nm
C) 0.55Nm
D) 0.21 Nm
Correct Answer: D
Solution :
[d] \[\tau \times \Delta t=I\omega \] or \[\tau \times 60=2\times 2\times 60\pi /60\Rightarrow \tau =0.21N-m\] \[(\because \,\,f=60rpm\,\therefore \omega =2\pi f=2\pi \times \frac{60}{60})\]
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