A) \[\sqrt{3}\times 0.16\]
B) \[\sqrt{3}\times 0.08\]
C) \[\sqrt{3}\times 0.1\]
D) Data insufficient
Correct Answer: B
Solution :
[b] \[10\cos {{30}^{o}}-f=2a\] ?(i) \[\tau =I\alpha \] \[\Rightarrow \,\,\,{{f}_{r}}=\frac{2}{3}\times 2\times {{r}^{2}}\times \alpha \] ? (ii) (where r is radius of sphere) From (i) and (ii), we get \[f=2\sqrt{3}\] newton, \[N=20+10\sin \,\,{{30}^{o}}=25\] \[f=\mu N\Rightarrow \mu =\frac{f}{N}=\frac{2\sqrt{3}}{25}=0.08\times \sqrt{3}\]You need to login to perform this action.
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