A) 2:1
B) 1:2
C) \[\sqrt{2}:1\]
D) \[1:\sqrt{2}\]
Correct Answer: D
Solution :
[d] \[K=\frac{{{L}^{2}}}{2I}\Rightarrow {{L}^{2}}=2KI\Rightarrow L=\sqrt{2KI}\] \[\frac{{{L}_{1}}}{{{L}_{2}}}=\sqrt{\frac{{{K}_{1}}}{{{K}_{2}}}.\frac{{{I}_{1}}}{{{I}_{2}}}}=\sqrt{\frac{K}{K}.\frac{I}{2I}=}\frac{1}{\sqrt{2}}\] \[\Rightarrow {{L}_{1}}:{{L}_{2}}=1:\sqrt{2}\]
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