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JEE Main & Advanced Physics Rotational Motion Question Bank Self Evaluation Test - System of Particles Rotational Motion

  • question_answer
    A thin ring, a disk and an annular cylinder, of same mass M, are released from a point 3.6m from the ground up an inclined plane of \[30{}^\circ \] degree inclination. The ring and the disk have the same radius R. Times taken by the ring and disk to reach the ground are in the ratio,

    A) \[\sqrt{2}:\sqrt{1.5}\]      

    B)        \[\sqrt{1.4}:\sqrt{1.5}\]

    C) \[\sqrt{1.5}:\sqrt{1.5}\]    

    D)        \[\sqrt{1.5}:\sqrt{1.6}\]

    Correct Answer: A

    Solution :

    [a] \[t=\frac{1}{\sin }\theta \sqrt{\frac{2h}{g}\left[ 1+\frac{{{K}^{2}}}{{{R}^{2}}} \right]}\Rightarrow t\propto \left( 1+\frac{{{K}^{2}}}{{{R}^{2}}} \right)\] \[so,\,\,\,{{t}_{1}}:{{t}_{2}}=\sqrt{2}:\sqrt{1.5}\]


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