A) IIIrd group
B) IInd group
C) Ist group
D) zero group
Correct Answer: B
Solution :
[b] \[_{58}Ce\] is lanthanoid. Lanthanoid are from 57 to 71 all present in IIIrd group. Hence \[_{58}Ce\] forms \[_{56}X\] element on emission of one \[\alpha \] particle with belongs to IInd group.You need to login to perform this action.
You will be redirected in
3 sec