A) there is no reaction
B) water gas is formed
C) \[S{{O}_{2}}\] and \[C{{O}_{2}}\] are evolved
D) CO and \[S{{O}_{2}}\] are evolved
Correct Answer: C
Solution :
[c] Charcoal is a pure form of carbon, its reaction with hot cone. \[{{H}_{2}}S{{O}_{4}}\] is as follows: \[C+2{{H}_{2}}S{{O}_{4}}\xrightarrow{{}}2{{H}_{2}}O+2S{{O}_{2}}+C{{O}_{2}}\]
You need to login to perform this action.
You will be redirected in
3 sec
