question_answer

\[\left( S{{i}_{2}}{{O}_{5}} \right)_{n}^{2n-}\] anion is obtained when:

A) no oxygen of a \[SiO_{4}^{4-}\] 'tetrahedron is shared with another \[SiO_{4}^{4-}\] tetrahedron

B) one oxygen of a \[SiO_{4}^{4-}\] tetrahedron is shared with another \[SiO_{4}^{4-}\] tetrahedron

C) two oxygen of a \[SiO_{4}^{4-}\] tetrahedron are shared with another \[SiO_{4}^{4-}\] tetrahedron

D) three oxygen of a \[SiO_{4}^{4-}\] tetrahedron are shared with another \[SiO_{4}^{4-}\] tetrahedron

Correct Answer: D

Solution :

[d] Total No. oxygen atoms per silicon atom \[=\frac{1}{2}+\frac{1}{2}+\frac{1}{2}+1=2.5\] \[\therefore \] Formula \[S{{i}_{2}}O_{5}^{2-}.\]