A) \[{{R}_{4}}Si\]
B) \[{{R}_{2}}SiC{{l}_{2}}\]
C) \[RSiC{{l}_{3}}\]
D) \[{{R}_{3}}SiCl\]
Correct Answer: A
Solution :
[c] The cross linked polymers will be formed by \[RSiC{{l}_{3}}\] \[nRSiC{{l}_{3}}\xrightarrow[-3nHCl]{3n{{H}_{2}}O}nR-\underset{OH}{\overset{OH}{\mathop{\underset{|}{\overset{|}{\mathop{Si}}}\,}}}\,-OH\xrightarrow{{}}\]
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