JEE Main & Advanced Chemistry The p-block Elements-II / p-ब्लॉक तत्व-II Question Bank Self Evaluation Test - The p-Block Elements (Group 13 and Group 14)

  • question_answer
    Ge(II)compounds are powerful reducing agents whereas Pb(IV)compounds are strong oxidants. It is because

    A) Pb is more electropositive than Ge

    B) ionization potential of lead is less than that of Ge

    C) ionic radii of \[P{{b}^{2+}}\]and \[P{{b}^{4+}}\] are larger than those of \[G{{e}^{2+}}\] and \[G{{e}^{4+}}\]

    D) of more pronounced inert pair effect in lead than in Ge

    Correct Answer: D

    Solution :

    [d] Ge(II) tends to acquire Ge (IV) state by loss of electrons. Hence it is reducing in nature. Pb (IV) tends to acquire Pb (II) O.S. by gain of electrons. Hence it is oxidising in nature. This is due to inert pair effect.


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