A) \[N{{O}_{2}}\] and \[{{O}_{2}}\]
B) \[{{N}_{2}}O\] and NO
C) NO and \[{{O}_{2}}\]
D) \[N{{H}_{3}}\] and \[HCl\]
Correct Answer: C
Solution :
[c] \[2NO+{{O}_{2}}\to 2N{{O}_{2}}\] brown
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