A) \[{{H}_{3}}{{P}_{3}}{{O}_{10}}\]
B) \[{{H}_{6}}{{P}_{4}}{{O}_{13}}\]
C) \[{{H}_{5}}{{P}_{5}}{{O}_{15}}\]
D) \[{{H}_{7}}{{P}_{5}}{{O}_{16}}\]
Correct Answer: C
Solution :
[c] \[{{H}_{5}}{{P}_{5}}{{O}_{15}}\] or\[{{\left( HP{{O}_{3}} \right)}_{5}}\]. It is metaphosphoric acid which is a cyclic phosphate.
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