A) \[PC{{l}_{5}},POC{{l}_{3}},{{H}_{3}}P{{O}_{3}}\]
B) \[PC{{l}_{5}},POC{{l}_{3}},{{H}_{3}}P{{O}_{4}}\]
C) \[SOC{{l}_{2}},POC{{l}_{3}},{{H}_{3}}P{{O}_{3}}\]
D) \[PC{{l}_{3}},POC{{l}_{3}},{{H}_{3}}P{{O}_{4}}\]
Correct Answer: B
Solution :
[b] \[\underset{A}{\mathop{PC{{l}_{5}}}}\,+{{H}_{2}}O\xrightarrow{{}}\underset{B}{\mathop{POC{{l}_{3}}}}\,+2HCl\] \[\underset{(B)}{\mathop{POC{{l}_{3}}}}\,+3{{H}_{2}}O\xrightarrow{{}}\underset{(C)}{\mathop{{{H}_{3}}P{{O}_{4}}}}\,+3HCl\]
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