A) by passing impure \[P{{H}_{3}}\] gas through a freezing mixture.
B) by passing the impure \[P{{H}_{3}}\] gas through HI and then its treatment with KOH (aq).
C) by both [a] and [b]
D) by none of these.
Correct Answer: C
Solution :
[c] Both the methods [a] and [b] can be used. When passed through freezing mixture the \[{{P}_{2}}{{H}_{4}}\] present condenses and pure \[P{{H}_{3}}\] is obtained. When passed through HI, \[P{{H}_{3}}\] is absorbed forming \[P{{H}_{4}}I.P{{H}_{4}}I\] when treated with \[KOH\left( aq \right)\] yields pure phosphine. \[P{{H}_{3}}+HI\xrightarrow{{}}P{{H}_{4}}I\] \[P{{H}_{4}}I+KOH\left( aq \right)\xrightarrow{{}}KI+{{H}_{2}}O+P{{H}_{3}}\uparrow \]
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