A) \[N{{O}_{2}}\] can be prepared by heating\[Pb{{\left( N{{O}_{3}} \right)}_{2}}\].
B) \[N{{O}_{2}}\] is red - brown gas.
C) \[N{{O}_{2}}\] is diamagnetic.
D) \[N{{O}_{2}}\] readily dimerises to \[{{N}_{2}}{{O}_{4}}\].
Correct Answer: C
Solution :
[c] \[N{{O}_{2}}\] is paramagnetic and readily dimerises to \[{{N}_{2}}{{O}_{4}}\] which is diamagnetic.
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