A) oxidizes \[HBr\].
B) reduces \[HBr\].
C) causes disproportionation of \[HBr\].
D) reacts too slowly with KBr.
Correct Answer: A
Solution :
[a] \[2HBr+{{H}_{2}}S{{O}_{4}}\to B{{r}_{2}}+2{{H}_{2}}O+S{{O}_{2}}\] \[HBr\] is oxidised to \[B{{r}_{2}}\]
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