A) oxidation of Mn in\[KMn{{O}_{4}}\] and production of\[C{{l}_{2}}\].
B) reduction of Mn in \[KMn{{O}_{4}}\] and production of \[{{H}_{2}}\].
C) oxidation of Mn in \[KMn{{O}_{4}}\] and production of \[{{H}_{2}}\].
D) reduction of Mn in \[KMn{{O}_{4}}\] and production of\[C{{l}_{2}}\].
Correct Answer: D
Solution :
[d] \[2\overset{+1}{\mathop{KM}}\,n{{O}_{4}}+16HCl\to 2\overset{+2}{\mathop{Mn}}\,C{{l}_{2}}+2KCl\] \[+8{{H}_{2}}O+5C{{l}_{2}}\] O.S of Mn changes from +7 to +2 hence reduction occurs and \[C{{l}_{2}}\] is formed.
You need to login to perform this action.
You will be redirected in
3 sec
