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JEE Main & Advanced Chemistry The p-block Elements-II / p-ब्लॉक तत्व-II Question Bank Self Evaluation Test - The p-Block Elements (Group 15, 16, 17 & 18)

  • question_answer
    One mole of fluorine is reacted with two moles of hot and concentrated \[KOH\]. The products formed are \[KF,{{H}_{2}}O\] and\[{{O}_{2}}\] . The molar ratio of \[KF,{{H}_{2}}O\] and \[{{O}_{2}}\] respectively is

    A) 1:1:2                            

    B) 2:1:0.5

    C) 1:2:1                            

    D) 2:1:2

    Correct Answer: B

    Solution :

    [b] \[2{{F}_{2}}+4KOH\to 4KF+{{O}_{2}}+2{{H}_{2}}O\] for 1 mole of \[{{F}_{2}}\] the molar ratio. \[\begin{matrix}    {{F}_{2}} & KOH & KF & {{O}_{2}} & {{H}_{2}}O  \\    1 & 2 & 2 & \frac{1}{2} & 1  \\ \end{matrix}\]


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