A) HF
B) \[HN{{O}_{3}}\]
C) HF and \[HN{{O}_{3}}\]
D) None of these
Correct Answer: B
Solution :
[b] In \[HN{{O}_{3}}+HF\to {{H}_{2}}\overset{+}{\mathop{N}}\,{{O}_{3}}+{{F}^{-}}HN{{O}_{3}}\] accepts \[{{H}^{+}}\] hence it is a base.
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