A) \[C{{l}_{2}}O\]
B) \[Cl{{O}_{3}}\]
C) \[Cl{{O}_{2}}\]
D) \[CI{{O}_{4}}\]
Correct Answer: C
Solution :
[c] Pure \[Cl{{O}_{2}}\] is obtained by passing dry \[C{{l}_{2}}\] Over \[AgCl{{O}_{3}}\] at \[90{}^\circ C\]. \[2AgCl{{O}_{3}}+C{{l}_{2}}\left( dry \right)\xrightarrow{90{}^\circ C}\] \[2AgCl+2Cl{{O}_{2}}+{{O}_{2}}\]
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