A) \[Xe{{F}_{4}}\]
B) \[XeO{{F}_{2}}\]
C) \[XeO{{F}_{4}}\]
D) \[Xe{{O}_{3}}\]
Correct Answer: B
Solution :
[b] \[Xe{{F}_{4}}+{{H}_{2}}O\to 2HF+XeO{{F}_{2}}\]
You need to login to perform this action.
You will be redirected in
3 sec
