question_answer

The geometry of \[XeO{{F}_{4}}\] by VSEPR theory is:

A) pentagonal planar

B) octahedral

C) square pyramidal

D) trigonal bipyramidal

Correct Answer: C

Solution :

[c] In \[XeO{{F}_{4}},Xe\] is \[s{{p}^{3}}{{d}^{2}}\] hybridised