A) \[L{{i}_{2}}{{O}_{2}},N{{a}_{2}}{{O}_{2}}\] and \[K{{O}_{2}}\]
B) \[L{{i}_{2}}O,N{{a}_{2}}{{O}_{2}}\]and \[K{{O}_{2}}\]
C) \[L{{i}_{2}}O,N{{a}_{2}}O\] and \[K{{O}_{2}}\]
D) \[Li{{O}_{2}},N{{a}_{2}}{{O}_{2}}\]and \[{{K}_{2}}O\]
Correct Answer: B
Solution :
[b] On heating with excess of air \[Li,\text{ }Na\]and \[K\]forms following oxides \[4Li+{{O}_{2}}\xrightarrow{{}}\underset{Lithium\,\,monoxide}{\mathop{2L{{i}_{2}}O}}\,\] \[4Na+{{O}_{2}}\xrightarrow{575K}\underset{Sodium\text{ }peroxide}{\mathop{N{{a}_{2}}{{O}_{2}}}}\,\] \[K+{{O}_{2}}\xrightarrow{{}}\underset{~Potassium\text{ }superoxide}{\mathop{K{{O}_{2}}}}\,\]
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