A) \[A{{l}_{4}}{{C}_{3}}+{{H}_{2}}O\xrightarrow{{}}CH\equiv CH\]
B) \[Ca{{C}_{2}}+{{H}_{2}}O\xrightarrow{{}}CH\equiv CH\]
C) \[M{{g}_{4}}{{C}_{3}}+{{H}_{2}}O\xrightarrow{{}}C{{H}_{3}}C\equiv CH\]
D) \[B{{e}_{2}}C+{{H}_{2}}O\xrightarrow{{}}C{{H}_{4}}\]
Correct Answer: A
Solution :
[a] \[A{{l}_{4}}{{C}_{3}}+12{{H}_{2}}O\xrightarrow{{}}4Al{{(OH)}_{3}}+3C{{H}_{4}}\]
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