A) 276 pm
B) 138 pm
C) 552 pm
D) 415 pm
Correct Answer: C
Solution :
[c] In a fcc lattice, the distance between the cation and anion is equal to the sum of their radii, which is equal to half of the edge length of unit cell, i.e.\[~{{r}^{+}}+{{r}^{-}}=\frac{a}{2}\] (where a = edge length) \[{{r}^{+}}=95pm,\,\,{{r}^{-}}=181pm\] Edge length \[=2{{r}^{+}}+2{{r}^{-}}=(2\times 95+2\times 181)pm\] \[=\left( 190+362 \right)pm=552pm.\]You need to login to perform this action.
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