A) 100% occupancy of tetrahedral voids, C.N. of \[B=4\]
B) 100% occupancy of octahedral voids, C.N. of B=4
C) 50% occupancy of tetrahedral voids, C.N. of A=4
D) 100% occupancy of octahedral voids, C.N. of A =4
Correct Answer: A
Solution :
[a] Number of A cations per unit cell = 4 Number of B anions per unit cell must be \[=2\times 4=8\] Number of tetrahedral voids per unit cell \[=2\times 4=8\] Number of octahedral voids per unit all \[=1\times 4=4.\] Hence, occupancy of tetrahedral voids =100%You need to login to perform this action.
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