A) 314.20 pm
B) 1.41 pm
C) 200 pm
D) 216 pm
Correct Answer: C
Solution :
[c] For bcc structure \[d=\frac{\sqrt{3}a}{2}\] where d' = distance between two atoms a = edge length \[1.73=\frac{\sqrt{3}}{2}a\] \[a=\frac{2\times 1.73}{\sqrt{3}}=2\overset{{}^\circ }{\mathop{A}}\,=200pm\]You need to login to perform this action.
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