A) \[10.376g/c{{m}^{3}}\]
B) \[5.188g/c{{m}^{3}}\]
C) \[7.289\text{ }g/c{{m}^{3}}\]
D) \[2.144g/c{{m}^{36}}\]
Correct Answer: B
Solution :
[b] \[\rho =\frac{Z\times M}{{{N}_{A}}\times {{a}^{3}}}\] \[=\frac{2\times 100}{6.023\times {{10}^{23}}\times {{\left( 400\times {{10}^{-10}} \right)}^{3}}}\] \[=5.188g/c{{m}^{3}}\]You need to login to perform this action.
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