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NEET Chemistry The Solid State / ठोस प्रावस्था Question Bank Self Evaluation Test - The Solid State

  • question_answer
    If \[NaCl\] is doped with \[{{10}^{-4}}mol\text{ }%\] of \[SrC{{l}_{2}}\], the concentration of cation vacancies will be \[({{N}_{A}}=6.02\times {{10}^{23}}mo{{l}^{-1}})\]

    A) \[6.02\times {{10}^{16}}mo{{l}^{-1}}\]         

    B) \[6.02\times {{10}^{17}}mo{{l}^{-1}}\]

    C) \[6.02\times {{10}^{14}}mo{{l}^{-1}}\]        

    D) \[6.02\times {{10}^{15}}mo{{l}^{-1}}\]

    Correct Answer: B

    Solution :

    [b] Since each \[S{{r}^{++}}\] ion provides one cation vacancy, hence Concentration of cation vacancies = mole % of \[SrC{{l}_{2}}\] added \[={{10}^{-4}}\text{mole}\]% \[=\frac{{{10}^{-4}}}{100}\times 6.023\times {{10}^{23}}=6.023\times {{10}^{17}}\]


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