A) \[58{}^\circ C\]
B) \[68{}^\circ C\]
C) \[73{}^\circ C\]
D) \[78{}^\circ C\]
Correct Answer: B
Solution :
[b] Let the final temperature be T. Then \[200\times 1\times \left( T-20 \right)+20\times \left( T-20 \right)\] =440(92 - T) Solving it, we get \[\operatorname{T}=68{}^\circ C.\].You need to login to perform this action.
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