A) \[\frac{2}{3}\]
B) \[\frac{1}{2}\]
C) 1
D) \[\frac{1}{3}\]
Correct Answer: D
Solution :
[d] the thermal resistance is given by \[\frac{x}{KA}+\frac{4x}{2KA}=\frac{x}{KA}+\frac{2x}{KA}=\frac{3x}{KA}\] \[\therefore \frac{dQ}{dt}=\frac{\Delta T}{\frac{3x}{KA}}=\frac{\left( {{T}_{2}}-{{T}_{1}} \right)KA}{3x}\] \[=\frac{1}{3}\left\{ \frac{A\left( {{T}_{2}}-{{T}_{1}} \right)K}{x} \right\}\therefore f=\frac{1}{3}\]You need to login to perform this action.
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