A) \[\]
B) \[6\times {{10}^{-6}}/{}^\circ C\]
C) (c)\[36\times {{10}^{-6}}/{}^\circ C\]
D) \[27\times {{10}^{-6}}/{}^\circ C\]
Correct Answer: A
Solution :
[a] \[{{\gamma }_{real}}={{\gamma }_{app.}}+{{\gamma }_{vessel}}\] So \[{{\left( {{\gamma }_{\operatorname{app}.}}+{{\gamma }_{vessel}} \right)}_{glass}}={{\left( {{\gamma }_{app }}+{{\gamma }_{vessel}} \right)}_{steel}}\] \[\Rightarrow 153\times {{10}^{-6}}+{{\left( {{\gamma }_{vessel}} \right)}_{glass}}\] \[=144\times 1{{0}^{-6}}+{{\left( {{\gamma }_{vessel}} \right)}_{steel}}\] \[\operatorname{Further}{{({{\gamma }_{vessel}})}_{steel}}=3\alpha =3\times (12\times 1{{0}^{-6}})\] \[=36\times {{10}^{-6}}{{/}^{o}}C\] \[\Rightarrow 153\times 1{{0}^{-6}}+{{\left( {{\gamma }_{vessel}} \right)}_{glass}}\] \[=144\times 1{{0}^{-6}}+36\times l{{0}^{-6}}\] \[{{\left( {{\gamma }_{vessel}} \right)}_{gIass}}=3\alpha =27\times 10{{/}^{o}}C\] \[\Rightarrow a=9\times {{10}^{-6}}/{}^\circ C\]You need to login to perform this action.
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