A) 560 cal/g
B) 550 cal/g
C) 540 cal/g
D) 530 cal/g
Correct Answer: B
Solution :
[b] As \[\operatorname{Pt}=mC\Delta T\] So, \[\operatorname{P}\times 10\times 60 = mC 100\] ...(i) and \[\operatorname{P}\times 55\times 60 = mL\] ...(ii) Dividing equation (i) by (ii) we get \[(\theta -{{\theta }_{0}})\] \[\therefore L = 550 cal./g.\]You need to login to perform this action.
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